(6x² + x2-1) (3x²+2x-1 (2x+3x+1)
Find square root
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1
Answer:
Given, 3x
2
−2
6
x+2=0
⇒x
2
−
3
2
6
x=−
3
2
⇒x
2
−
3
2
6
x+(
3
6
)
2
=(
3
6
)
2
−
3
2
⇒x
2
−2x×
3
6
+(
3
6
)
2
=
9
6
−
3
2
⇒(x−
3
6
)
2
=
9
6−6
⇒x−
3
6
=0
⇒x=
3
6
⇒x=
3
×
3
2
×
3
⇒x=
3
2
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