Math, asked by sam2111999, 1 year ago

6x²x² + 8x³ + 27x² + 7 ÷ 3x² + 4x + 1 = ?

Answers

Answered by vivek2001
2
6x²x²+8x³+27x+7÷3x²+4x+1
=6x⁴+8x³+27x+7÷3x²+4x+1
multiplying 3x²+4x+1 by 2x² we get,6x⁴+8x³+2x²-------(1) and subtracting (1) by 6x⁴+8x³27x+7we get,2x²+27x+7---------(2) [6x⁴+8x³ gets cancelled out from 6x⁴+8x³+27x+7]
again by multiplying 3x²+4x+1 by 1 we get,same 3x²+4x+1----------------(3)
again subtracting (3) from (2) we get,-x²+23x+6 as remainder it can not be divided further.

The answer is 2x²+1(see the bold and italic letters n nos. this shows the ans)
And the remainder is -x²+23x+1.

Answered by adityagupta
2
the right answer of the question is 3x24x1.
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