Math, asked by ayan9967348517, 5 months ago

6x2y2-7x2y+4xy2+11 from5x2y2-3x2y+5xy2+7​

Answers

Answered by khashrul
0

Answer:

(5x^2y^2 - 3x^2y + 5xy^2 + 7) - (6x^2y^2 - 7x^2y + 4xy^2 + 11) = -x^2y^2 + 4x^2y + xy^2 - 4

Step-by-step explanation:

(5x^2y^2 - 3x^2y + 5xy^2 + 7) - (6x^2y^2 - 7x^2y + 4xy^2 + 11)

= (5x^2y^2 - 6x^2y^2) - (3x^2y - 7x^2y) + (5xy^2 - 4xy^2) + (7 - 11)  [rearranging like terms]

= -x^2y^2 + 4x^2y + xy^2 - 4

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