Question

6x3-11x2+kx-20 find the value of k when x=4/3​

Answer 1

hey mate:

given here

6x³-11x²+kx-20=0

put value of x= 4/3

then,

6(4/3)³-11(4/3)²+k 4/3-20=0

=>6 × 64/27. - 11×16/9+4/3k -20=0

=>128/9 - 176/9 + 4/3k -20=0

=>(128-176+12k-180)=0

=>(128-356+12k)=0

=>12k=228

=>k=228/12

=>k=19

I hopes its helps u.

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