Question

6x³+3x² -7x+5 find the derivatives

Answer 1

Answer:

9-7x+5

7x+5+9

7x+14

x=14/7

x=2

Answer 2

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$\frac{d \:(6 {x}^{3} +3 {x}^{2} -7x+5 ) }{dx} \\ = \frac{d \: 6 {x}^{3} }{dx} + \frac{d \: 3 {x}^{2} }{dx} - \frac{d \: \: 7x}{dx} + \frac{d \: 5}{dx} \\ = 6 \times 3 {x}^{2} + 3 \times 2x - 7 + 0 \\ = 18 {x}^{2} + 6x - 7$