Question

6x³-8x²+3x+7 need help​

Answer 1

Answer:

what should we do in the answer

Step-by-step explanation:

first tell then I will help you

Answer 2

$f(x) = 6 {x}^{3} - 8 {x}^{2} + 3x + 7 = 0$

Then, Δ = –51508 < 0

Therefore, there exists only one real solution.

$x_{1} = \frac{8 - \sqrt[3]{ 3538 + 18 \sqrt{38631} } - \sqrt[3]{ 3538 - 18 \sqrt{38631} } }{18}$

$x_{2,3} = \frac{16 + \sqrt[3]{3538 + 18 \sqrt{38631} } + \sqrt[3]{3538 - 18 \sqrt{38631} } + i\sqrt{3}( ± \sqrt[3]{3538 + 18 \sqrt{38631} }∓ \sqrt[3]{3538 - 18 \sqrt{38631} } ) }{36}$