Math, asked by dhanvimodi7676, 8 days ago

(6x³y²z-5)(3x+2)
solve with step by step​

Answers

Answered by bhavyarathod0909
1

Answer:

Step-by-step explanation:

How to solve your problem

(

6

3

2

5

)

(

3

+

2

)

(6x^{3}y^{2}z-5)(3x+2)

(6x3y2z−5)(3x+2)

Simplify

1

Distribute

(

6

3

2

5

)

(

3

+

2

)

{\color{#c92786}{(6x^{3}y^{2}z-5)(3x+2)}}

(6x3y2z−5)(3x+2)

6

(

3

+

2

)

3

2

5

(

3

+

2

)

{\color{#c92786}{6z(3x+2)x^{3}y^{2}-5(3x+2)}}

6z(3x+2)x3y2−5(3x+2)

2

Distribute

6

(

3

+

2

)

3

2

5

(

3

+

2

)

{\color{#c92786}{6z(3x+2)x^{3}y^{2}}}-5(3x+2)

6z(3x+2)x3y2−5(3x+2)

1

8

4

2

+

1

2

3

2

5

(

3

+

2

)

{\color{#c92786}{18zx^{4}y^{2}+12zx^{3}y^{2}}}-5(3x+2)

18zx4y2+12zx3y2−5(3x+2)

3

Distribute

1

8

4

2

+

1

2

3

2

5

(

3

+

2

)

18zx^{4}y^{2}+12zx^{3}y^{2}{\color{#c92786}{-5(3x+2)}}

18zx4y2+12zx3y2−5(3x+2)

1

8

4

2

+

1

2

3

2

1

5

1

0

18zx^{4}y^{2}+12zx^{3}y^{2}{\color{#c92786}{-15x-10}}

18zx4y2+12zx3y2−15x−10

Solution

1

8

4

2

+

1

2

3

2

1

5

1

0

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