Question

6xsquare - x - 1 = 0 , find its quadratic root.

Answer 1

Answer:

$6 {x}^{2} - x - 1 = 0$

${6x}^{2} + 2x - 3x - 1 = 0$

$2x(3x + 1) - 1(3x + 1) = 0$

$(2x - 1)(3x + 1) = 0$

So, the roots are :

$x = \frac{1}{2}$

and

$x = \frac{ - 1}{3}$