Question

6xy^2 - Зxy - 10у + 5​

Answer 1

Step-by-step explanation:

ax2

+6xy+by

2

−10x+10y−6=0 represent pair of lines when

Δ=0

⇒

∣

∣

∣

∣

∣

∣

∣

∣

a

3

−5

3

b

5

−5

5

−6

∣

∣

∣

∣

∣

∣

∣

∣

=0

⇒a(−6b−25)−3(−18+25)−5(15+5b)=0

⇒−6ab−25a−21−75−25b=0

⇒25a+25b+6ab+96=0 ...(1)

And represent pair of perpendicular lines when

a+b=0 ...(2)

Solving (1) and (2)

−6a

2

+96=0⇒a

2

=16⇒∣a∣=4 please mark as brainlliest