Math, asked by srishty42, 10 months ago

6y + 1 upon 2 + 1 equals to 7 Y minus 3 upon 3​

Answers

Answered by aditya157663069
2

Answer:

6

Step-by-step explanation:

y+1/3=7y-3/3

cancle 3 because they divides themselves

now,

y+1=7y-1

take 7y-1 in left hand side

we get,

y+1-7y+1=0

-6y+2=0

-6y=-2

y==1/3

Answered by Anonymous
3

Answer:

6y+1÷2+1=7y-3 ÷3

3(6y+1)=2+1(7y-3)

18+3=2+1(7y-3)

18+3=3(7Y-3)

18+3=21y-3

18y-21y=-3-3

-3y=-9

y=9/3

y=3

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