Question

6y^2-28y^3+3y^2+30y-9 by 2y^2 -6

Answer 1

Answer:

$= > \frac{ 6 {y}^{2} - 28 {y}^{3} + 3 {y}^{2} + 30y - 9}{2 {y}^{2} - 6} \\ = > \frac{ - 28{y}^{3} + 9 {y}^{2} + 30y - 9 }{2 {y}^{2} - 6 }$

$let \: \: 2 {y}^{2} - 6 = 0 \\ = > 2 {y}^{2} - 6 = 0 \\ = > 2 {y}^{2} = 6 \\ = > {y}^{2} = 3 \\ = > y = \sqrt{3}$

$= > - 28 { (\sqrt{3}) }^{3} + 9 { (\sqrt{3}) }^{2} + 30( \sqrt{3} ) - 9 \\ = > - 84 \sqrt{3} + 27 + 30 \sqrt{3} - 9 \\ = > 18 - 54 \sqrt{3} \\ = > 18(1 - 3 \sqrt{3} ) \\ = > 18(1 - 3 \times 1.73) \\ = > 18(1 -5 .19) \\ = > 18( - 4.19) \\ = > - 75.42$

Hope this answer helps you ^_^ !