(√6y square +7y+√6)
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Answered by
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Step-by-step explanation:
Given quadratic equation is √7 y 2
−6y−13
7
=0
Comparing it with the standard form of equation ax
2
+bx+c we get a=7,b=6,c=13
7
Therefore, x=
2a
−b±
b
2
−4ac
=
2
7
−(−6)±
(−6)
2
−4×
7
×(−13
7
)
=
2
7
6±
36+364
=
2
7
6±
400
=
2
7
6±20
=
2
7
6−20
=
2
7
−14
=
7
−7
=
7
×
7
−7×
7
=−
7
=
2
7
6+20
=
2
7
26
=
7
13
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