(√6y square +7y+√6)=?
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Answered by
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Answer:
√6y² + 7y + √6 = 0
multiplying both sides by √6,
6y² + 7√6y + 6 = 0
6y² + 6√6y + √6y + 6 = 0
6y ( y + √6 ) + √6 ( y + √6 ) = 0
( 6y + √6 ) ( y + √6 ) = 0
√6 ( y + √6 ) ( y + √6) = 0
y = -√6, -√6
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