6years ago a man age was six times the age of his son . After 4years thrice his age will be equal to eight times his son age . What are there present age.
Answers
Answer:
during the first two years of his life and the death
Step-by-step explanation:
I am a man far more by the time the theory goes in
The present age of son is 11 Years
The present age of the man is 36 Years
Explanation:
Given:
1. 6years ago a man's age was six times the age of his son
2. After 4years thrice his age will be equal to eight times his son age.
To find:
The present age of son and man
Solution:
==> Present age of Man = x
==> Present age of Son = y
==> 6 years Ago
After 4years thrice his age will be equal to eight times his son age . What==> Before 6 years , Man age = (x-6)
==> Before 6 years , Son age = (y-6)
==> 6years ago a man's age was six times the age of his son
==> (x-6) = 6(y-6)
==> x-6 = 6y-36
==> x=6y-36+6
==> x = 6y-30
==> x-6y=-30 ==>1
==> After 4years
==> After 4 years , Man age = (x+4)
==> Before 4 years , Son age = (y+4)
==> After 4years thrice his age will be equal to eight times his son age
==> 3(x+4)= 8(y+4)
==> 3x+12 =8y+32
==> 3x = 8y+32-12
==> 3x = 8y +20
==> 3x-8y = 20 ==> 2
==>Using Elimination Method,
==> x-6y =-30
==> Multiply by 3 in equation 1
==> 3(x-6y=-30)
==> 3x-18y=-90==> 3
==> Multiply by -1 in equation 2
==> -(3x-8y=20)
==> -3x+8y=-20 ==> 4
==> Equating equation 3 and 4
==> 3x-18y =-90
==> -3x+8y =-20
___________
-10y= -110
_____________
==> -10y =-110
==> 10 y = 110
==> y = 11 Years
==> Substitute y value in equation 1
==> x-6y=-30
==> x-6(11)=-30
==> x -66 = -30
==> x =-30+66
==> x = 36 Years
The present age of son is 11 Years
The present age of the man is 36 Years