Question

6z-3z²-18z³ factorize the following

Answer 1

-18z*-3z*2+6z=0

18z*3+3z*2-6z=0

18z*3+12z*2-9z*2-6z=0

2z(9z*2+6z)-1(9z*2+6z)=0

(2z-1)(9z*2+6z)=0

z=1/2. z(9z+6)=0

z=0 9z+6=0

z=-6/9