Question

(7^0- 4^0)×(7^0+4^0)+(7^0×4^0)

Answer 1

SOLUTION :-

$(7 {}^{0} - {4}^{0} ) \times ( {7}^{0} + 4 {}^{0}) + ( {7}^{0} \times {4}^{0} ) \\ \\ = (1 - 1) \times (1 + 1) + (1 \times 1) \\ \\ = 0 \times 2 + 1 = 0 + 1 = 1$

∴ a⁰= 1