(7^0+5^0+2^0)^-3 answer
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aagney:
it is minus cube
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(7^0+5^0+2^0)^-3
=(1+1+1)^-3
=3^-3
=1/3^3
=1/27
Mark me brainliest
=(1+1+1)^-3
=3^-3
=1/3^3
=1/27
Mark me brainliest
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