Question

7^1÷2-1÷7^1÷2+1-7^1÷2+1÷7^1÷2-1=a+b×7^1÷2​

Answer 1

$({7}^{1} \div 2) - (1 \div {7}^{1} \div 2) + 1 - ( {7}^{1} \div 2) + (1 \div {7}^{1} \div 2) - 1 = a + b( {7}^{1} \div 2 )$

consider LHS

$\: \: \: \: \: ( {7}^{1} \div 2) - (1 \div {7}^{1} \div 2) + 1 - ( {7}^{1} \div 2) + (1 \div {7}^{1} \div 2) - 1 \\ = 3.5 - (1 \div 7 \div 2) + 1 - 3.5 + (1 \div 7 \div 2) - 1 \\ = 3.5 - 3.5 + 1 - 1 + (1 \div 7 \div 2) - (1 \div 7 \div 2) \\ = 0$