√7-1/√7+1=a+b√7 find a and b
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LHS=
√7-1...........√7+1
--------- - .....---------
√7+1.............√7-1
(√7-1)²-(√7+1)²
=-------------------
.........7-1
(7+1-2√7-7-1-2√7)
=-------------------------
..............6
-4√7
=------
...6
-2√7
=------
.....3
So, on comparing LHS with RHS
we get
a = 0 and b = -2/3
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