Math, asked by sankaracharya6949, 1 year ago

7+10(2x-3x)-8(2x-3x)^2

Answers

Answered by TheLostMonk
3
7 + 10 ( 2x - 3x ) - 8 ( 2x - 3x ) ^2






= 7 - 10x - 8 x ^2 =0






- ( 8x^2 + 10x - 7 ) =0








8x^2 + 10x - 7 = 0








8x^2 + 14x - 4x - 7 = 0







4x ( 2x - 1 ) + 7 ( 2x - 1 ) = 0








( 2x - 1 ) (4x + 7 ) = 0






x = 1 / 2 , -7 / 4
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