Question

7 + 10(2x - Зу) – 8
${(2x - 3y)}^{2}$
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Answer 1

Step-by-step explanation:

7+10(2x−3y)−8(2x−3y)

2

Let 2x−3y=z

Then,7+10(2x−3y)−8(2x−3y)

2

becomes

=7+10z−8z

2

=7+14z−4z−8z

2

=7(1+2z)−4z(1+2z)

=(1+2z)(7−4z)

Now, on substituting z=2x−3y, we get

=[(1+2(2x−3y))][7−4(2x−3y)]

=(1+4x−6y)(7−8x+12y)