7.125 g of an acid (MW = 114) is completely neutralized by 5 g of NaOH (MW = 40). What is the basicity of acid?
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Given,
7.125 g of an acid (Mol wt = 114 g/mol) is completely neutralised by 5g of NaOH (Mol wt. = 40g/mol)
To find,
The basicity of the given acid.
for complete neutralised solution,
no of equivalents of acid = no of equivalents of base.
⇒no of moles of acid × basicity of acid = no of moles of base × acidity of base.
⇒weight in g/mol weight × basicity = weight in g/mol weight × 1 [ acidity of NaOH = 1]
⇒7.125/114 × basicity = 5g/40
⇒1/16 × basicity = 1/8
⇒basicity = 2
Therefore basicity of acid is 2.
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