Question

7.125 g of an acid (MW = 114) is completely neutralized by 5 g of NaOH (MW = 40). What is the basicity of acid?


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Answer 1

Given,

7.125 g of an acid (Mol wt = 114 g/mol) is completely neutralised by 5g of NaOH (Mol wt. = 40g/mol)

To find,

The basicity of the given acid.

for complete neutralised solution,

no of equivalents of acid = no of equivalents of base.

⇒no of moles of acid × basicity of acid = no of moles of base × acidity of base.

⇒weight in g/mol weight × basicity = weight in g/mol weight × 1 [ acidity of NaOH = 1]

⇒7.125/114 × basicity = 5g/40

⇒1/16 × basicity = 1/8

⇒basicity = 2

Therefore basicity of acid is 2.