Question

7,14,21,28.........find 7 term of AP
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Answer 1

Answer: 49

Solution:

Given,

AP: 7, 15, 21, 28.......

Common Difference = a2 - a1

= 14 - 7

= 7

7th term of AP = a7 = a + 6d

= 7 + 6(7)

= 7 + 42

= 49

Therefore, the 7th term of AP is 49.

Answer 2

AnswEr:

First Term (a) = 7

Common Difference = $\sf\: a_1 \:-\: a_2$

$:\implies\sf\: 14 \: - \: 7$

$:\implies\large{\underline{\boxed{\sf{\red{d\:=\:7}}}}}$

We know that,

$:\implies\large{\underline{\boxed{\sf{\red{an \:=\: a \:+\: (n\;-\:1)d}}}}}$

Putting Values:-

$:\implies\sf\: an = 7 + (7 - 1)(7)$

$:\implies\sf\: an = 7 + 6 (7)$

$:\implies\sf\: an = 7 + 42$

$:\implies\sf\large{\underline{\boxed{\sf{\pink{an = 49}}}}}$

Hence, 7th term of the AP is 49.