7/15 of water in a tank which is full is used on one day, and 5/6 of the remainder on the next.If 80 litres are then left, how much water can the tank hold when full?
Answers
Answered by
6
Part of water of tank used = 7/15
Remaining = 1-7/15 = 8/15
Part of water used next day = (5/6)*(8/15) = 4/9
Remaining = 8/15 -4/9 = 4/45
Now 4/45 part contains = 80 litres
So, 1 part will contain = 80/(4/45) = 900 litres.
The capacity of tank is 900 litres.
Remaining = 1-7/15 = 8/15
Part of water used next day = (5/6)*(8/15) = 4/9
Remaining = 8/15 -4/9 = 4/45
Now 4/45 part contains = 80 litres
So, 1 part will contain = 80/(4/45) = 900 litres.
The capacity of tank is 900 litres.
Similar questions