Question

7(2-√5)/(2+√3) rationalize denominator​

Answer 1

$question = \frac{7(2 - \sqrt{5)} }{2 + \sqrt{3} } . \\ \\ solution. \\ \\ = \frac{7(2 - \sqrt{5)} }{2 + \sqrt{3} } \\ \\ = \frac{7(2 - \sqrt{5)} \times( 2 - \sqrt{3}) }{2 + \sqrt{3} \times 2 - \sqrt{3} } \\ \\ = \frac{(14 - 7 \sqrt{5}) \times (2 - \sqrt{3} ) }{ {2}^{2} - ( \sqrt{3} ) {}^{2} } \\ \\ = \frac{28 - 14 \sqrt{3} - 14 \sqrt{5} + 7 \sqrt{3} }{4 - 3} \\ \\ = \frac{28 - 7 \sqrt{3} - 14 \sqrt{5} }{1} \\ \\ = 7(4 - \sqrt{3} - 2 \sqrt{5} ) \: \: answer... \\ \\ \: \: rationalize \: denominator \: this \: question$

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thanks you so much sir...