Math, asked by THEGUY2641, 9 months ago

7,2√5 Compare the given pair of surd.

Answers

Answered by amitnrw
14

Answer:

7 > 2√5

Step-by-step explanation:

Given pair of  surds

7,  2√5

A = 7

B = 2√7

A² = (7)²  = 49

B² = (2√7)²  = 4 * 7 = 28

49 > 28

A² > B²

A > B

7 > 2√5

Answered by sushiladevi4418
5

Answer:

7 is greater than 2√5

Step-by-step explanation:

As per the given question,

Surd is define as the irrational root of an integer.

Given numbers are 7 , 2√5

2√5 is read as 2 times square root of 5 .

On calculating the value of 2 times square root of 5 that is 2√5 ,we get:

√5 is equals to,

√5 = 2.236

Therefore,

2√5  = 2× 2.236

         = 4.472

As we state that the number 7 is an integer whereas the number 2√5 is an irrational number.

Hence, 7 is greater than 2√5

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