Question

√7-√2÷√7-√2 rationalise the denominator

Answer 1

$\huge\mathbb{A~N~S~W~E~R}$

$= \frac{ \sqrt{7 } - \sqrt{2} }{ \sqrt{7} - \sqrt{2} } \\ \\ = \frac{ \sqrt{7} - \sqrt{2} }{ \sqrt{7} - \sqrt{2} } \times \frac{ \sqrt{7} + \sqrt{2} }{ \sqrt{7} + \sqrt{2} } \\ \\ = \frac{7 - 2}{7 - 2} \\ \\ = \frac{5}{5} \\ \\ = 1$

${\huge\color{Red}{Answer~is~1 }}$

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