Question

(√7+√2)÷ 9+ 2√15 simplify by rationalising the denominator​

Answer 1

Answer:

${ \large \bold \orange{ \underline{answer = \frac{9 \sqrt{5} - 2 \sqrt{35} + 9 \sqrt{2} - 2 \sqrt{10} }{61} }}}$

$\mathfrak{ \large \bold \green{ \underline{ \underline{question}}}} \\ { \large{\frac{ \sqrt{7} + \sqrt{2} }{9 + 2 \sqrt{5} } \: \: \: rationalising \: denominator}} \\ \\ { \large \bold \red{ \underline{solution}}} \\ { \large{{\frac{ \sqrt{7} + \sqrt{2} }{9 + 2 \sqrt{5}}}}} \times { \large{ \frac{9 - 2 \sqrt{5} }{9 - 2\sqrt{5} } }} \\ { \large{ \frac{( \sqrt{7} + \sqrt{2} )(9 - 2 \sqrt{5} )}{( {9})^{2} - (2 \sqrt{5} ) {}^{2} } }} \\ { \large{ \frac{9 \sqrt{5} - 2 \sqrt{35} + 9 \sqrt{2} - 2 \sqrt{10} }{81 - 20} }} \\ { \large{ \frac{9 \sqrt{5} - 2 \sqrt{35} + 9 \sqrt{2} - 2 \sqrt{10} }{61} }} \\ \\ { \large \bold \orange{ \underline{answer = \frac{9 \sqrt{5} - 2 \sqrt{35} + 9 \sqrt{2} - 2 \sqrt{10} }{61} }}}$