Question

(-7)^-2÷(90)^-1 find the multiplicative inverse ​

Answer 1

$Given \:number \: \frac{(-7)^{-2}}{90^{-1}}$

$= \frac{90^{1}}{(-7)^{2}}$

$\boxed { \pink { Since,a^{-n} = \frac{1}{a^{n}}}}$

$= \frac{90}{49}$

$Multiplicative \:inverse \: of \: \frac{90}{49}\:is\\\frac{-49}{90}$

Therefore.,

$\red { Multiplicative \:inverse \: of \:\frac{(-7)^{-2}}{90^{-1}}}$

$\green { = \frac{-49}{90} }$

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