Question

7=2^x solve by using logarithm

Answer 1

Given Question is 7 = 2^x.

log(7) = log(2^x)

log 7 = x log 2

x = log 7/log 2.


Hope this helps!

Answer 2

The answer is given below :

RULES :

log (x^n) = n logx

SOLUTION :

Given that,

7 = 2^x

Now, taking log, we get -

log7 = log (2^x)

=> log7 = x log2

=> x = (log7)/(log2)

=> x = 2.8 (approximately)

or, we can write

x = (log7)/(log2)

$= > x = log_{2}7$

Thank you for your question.