Question

КС
Зх
(7х+20)°
о
A
В
11. In the given figure, if ZBOC = (7x + 20°, ZCOA = 3x and ZAOB is a straight line, then x = ?
[Hint: ZBOC and ZCOA form a linear pair]

solve with procces​

Answer 1

Step-by-step explanation:

∠AOB becomes a straight line if ∠AOB=180∘∠AOB becomes a straight line if ∠AOB=180∘

Now, ∠AOB=∠BOC+∠COA∠AOB=∠BOC+∠COA

Therefore, 180∘=7x∘+20∘+3x∘180∘=7x∘+20∘+3x∘

=> 10x∘=160∘10x∘=160∘

=< x∘=16010=16∘

now write it in your own way by seeing this and your question