Question

7.25,894
1. Look at the numbers below, follow the clues, and all
7.25,307
7.25,893
3.72.581
Clues
a. I am an odd number
b. The sum of the digits in my thousands period is equal to
ones place
c. ir am rounded off to the nearest 1000. I will be 7.25.
Who am I?
Complete the puzzle by writing the numbers for the gh
The clues given in the puzzle will help you complete.​

Answer 1

Answer:

Problem 1: Compute the absolute error and relative error in approximations of p by p∗.

(Use calculator!)

a) p = π, p∗ = 22/7;

b) p = π, p∗ = 3.1416.

Solution: For this exercise, you can use either calculator or Matlab.

a) Absolute error: |p − p∗| = |π − 22/7| = 0.0012645.

Relative error: |p−p∗|

|p| = |π−22/7|

π = 4.0250 × 10−4.

b) Absolute error: |p − p∗| = |π − 3.1416| = 7.3464 × 10−6.

Relative error: |p−p∗|

|p| = |π−3.1416|

π = 2.3384 × 10−6.

Problem 2: Find the largest interval in which p∗ must lie to app

Explanation: