Question

7 2the power95+3 2the power58=?

Answer 1

i hope u understand .plz. mr
${21}^{153}$

Answer 2

Look I am not sure if ur asking for the last digit of the result of not but I am assuming it as I think it should be the possible question
For these kinds of sum u need to know the trends of powers
Here in this case for 7
7^1=7
7^2=49
7^3=343
7^4=2401
7^5=16807
7^6=117649
7^7=823543
7^8=5764801
Don't get tensed up :)
I will not go upto
7^95 Lol
I just wanted you to understand the trend of unit's place that is 7,9,3,1,7,9,3,1
so it's repeated 7,9,3,1
Now same for three it is 3,9,7,1
Now going back to your sum
First 7^95
so we divide 95 by 4 as the trend repeats after 4
remainder comes out to be 3
so the third number of trend for 7 is 3
For 3^58
58/4
remainder 2
second number of trend is 9
So we get unit's place of both the numbers
Add them
=3+9
=12
Now the one goes to carry so need not be considered
unit's place of result=2
HOPE IT HELPS
MARK AS BRAINLIEST