7/2x+1 + 13/y+2=27; 13/2x+1 + 7/y+2=33 please that is so important please sol it now
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We have,
2x+1
7
+
y+2
13
=27...(i)
and
2x+1
13
+
y+2
7
=33....(ii)
Substituting
2x+1
1
=a and
y+2
1
=b in equations (i) and (ii), we get
7a+13b=27...(iii)
and 13a+7b=33....(iv)
Adding equations (iii) and (iv), we get
20a+20b=60
a+b=3...(v)
Subtracting equation (iii) from equation (iv), we get
6a−6b=6
a−b=1...(vi)
Adding equations (v) and (vi), we get
2a=4⇒a=2
Putting the value of a in equation (v), we get
2+b=3⇒b=1
Resubstituting the values of a and b, we get
2x+1
1
=2 and
y+2
1
=1
1=4x+2 and 1=y+2
x=−
4
1
and y=−1
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