Question

7/2x+1 +13/y+2=27 13/2x+1+7/y+2=33 solve the simultaneous

Answer 1

7/(2x + 1) + 13/(y + 2) = 27

13/(2x + 1) + 7/(y + 2) = 33

Replacing 1/2x+1 = p

1/y+2 = q

7p + 13q = 27-------------( 1 )

13p + 7q = 33-------------( 2 )

adding-----------( 1 ) & -----------( 2 )

7p + 13q = 27

13p + 7q = 33

–····················–

20p + 20q = 60

p + q = 3-------------( 3 )

Subtracting-------( 1 ) & ----------( 2 )

7p + 13q = 27

13p + 7 q = 33

–······················–

-6p + 6q = -6

p - q = 1------------( 4 )

from---------( 3 ) & -----------( 4 )

p + q = 3

p - q = 1

–··········–

2p = 4

p = 2 [ put in -----( 1 ) ]

2 + q = 3

q = 1 , p = 2

p = 2 = 1/(2x + 1)

4x + 2 = 1

x = -1/4

q = 1 = 1/(y + 2)

y + 2 = 1

y = -1 , x = -1/4