7√2x^2-10x-4√2 with formula
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Answer :
The factorized form of the given polynomial is :
{7√(2)x + 4}{x - √(2)}
Given :
The quadratic polynomial is :
7√(2)x² - 10x -4√(2)
To Find :
The factorised form of the given polynomial :7√(2)x ² - 10x -4√(2)
Solution :
7√(2)x² - 10x - 4√(2)
= 7√(2)x² - 14x+ 4x - 4√(2)
= 7√(2)x{x - √(2)} + 4{x - √(2)}
= {7√(2)x + 4}{x - √(2)}
If it would give to find the zeroes of this polynomial then :
7√(2)x + 4 = 0 and x -√(2) = 0
⇒x = -4/{7√(2)} and ⇒x = √(2)
⇒x = -4×√2/(7×2) and ⇒x = √(2)
⇒x = -4√2/14 and ⇒x = √(2)
⇒x = -2√2/7 and ⇒x = √(2)
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