7√2x^2+9x+√2 find zeros of the polynomial
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Answered by
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Heya ______
→ zeroes of given polynomial are
- √2/7 or -1/√2
→ for further details refer to the attachment
_◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎
Hope it helps!!
→ zeroes of given polynomial are
- √2/7 or -1/√2
→ for further details refer to the attachment
_◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎
Hope it helps!!
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harsh1175:
very very thanks
Answered by
2
Hii friend,
7✓2X²+9X+✓2
7✓2X²+2X+7X+✓2
✓2X(7X+✓2) + 1(7X+✓2)
(7X+✓2) ( ✓2X+1)
(7X+✓2) = 0 OR. ( ✓2X+1) = 0
7X = -✓2 OR. ✓2X = -1
X= -✓2/7 OR X = -1/✓2
Hence,
-✓2/7 and -1/✓2 are the zeros of the polynomial
HOPE IT HELPS!!!!
7✓2X²+9X+✓2
7✓2X²+2X+7X+✓2
✓2X(7X+✓2) + 1(7X+✓2)
(7X+✓2) ( ✓2X+1)
(7X+✓2) = 0 OR. ( ✓2X+1) = 0
7X = -✓2 OR. ✓2X = -1
X= -✓2/7 OR X = -1/✓2
Hence,
-✓2/7 and -1/✓2 are the zeros of the polynomial
HOPE IT HELPS!!!!
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