7(2z)+4) - 10z = 3z-2 , find value of z
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Answered by
0
Answer:
z=(2−3i)
z
2
−4z+13
=(2−3i)
2
−4(2−3i)+13
=−5−12i−8+12i+13
=−12i+12i−5−8+13
=0
4z
3
−3z
2
+2z+170
=4(2−3i)
3
−3(2−3i)
2
+2(2−3i)+170
=4(−46−9i)−3(−5−12i)+2(2−3i)+170
=−184−36i−3(−5−12i)+2(2−3i)+170
=−184−36i+15+36i+4−6i+170
=5−6i
Answered by
6
7(2z) + 4 - 10z = 3z - 2
14z + 4 - 10z = 3z - 2
14z - 10z - 3z = - 2 - 4
14z - 13z = -6
z = -6
Hope this helps you
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14z + 4 - 10z = 3z - 2
14z - 10z - 3z = - 2 - 4
14z - 13z = -6
z = -6
Hope this helps you
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