х+у= 7, 3х – у = 1 by substituting method
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from x+y=7
x=7-y
putting value of x in 3x-y=1
3(7-y)-y=1
21-3y-y=1
21-4y=1
-4y=1-21
-4y=-20
y=5
x=7-y=7-5
x= 2
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