Question

7^3-2log7^8 simplyfy

Answer 1

by using multiple identity
3*7-8*2log7
21-16log7
21-16*0.8
21-13
=8 (approx)

Answer 2

Answer:

${8}^{ - 6}$

Step by step Explanation:

${ {7}^{3} }^{ - 2 log_{7}(8) } = x$

Log on both sides(take base as 7).Write 7^3 as 343 for now.

$log_{7}( {343}^{ -2 log_{7}(8) } ) = log_{7}(x)$

Apply formula log_m( a^b) = b log_m( a) and write - 2log_7(8) as Co efficient of log_7(343)

Then write log_7(343) as 3

Therefore,

$- 2 log_{7}(8) \times 3 = log_{7}(x) \\ \\ - 6 log_{7}(8) = log_{7}(x) \\ \\ log_{7}( {8}^{ - 6} ) = log_{7}(x)$

On Comparing we get x = 8^-6

Please mark as the brainliest if you found it helpful!