Question

7√3-5√2÷√48+√18 rationalize the denominator
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Answer 1

$\huge \pink {{SOLUTION}}$

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$= > \frac{7 \sqrt{3 } - 5 \sqrt{2} }{ \sqrt{48} + \sqrt{18} } \\ \\ = > \frac{7 \sqrt{3} - 5 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2} } \\ \\ = > \frac{7 \sqrt{3} - 5 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2} } \times \frac{4 \sqrt{3} - 3 \sqrt{2} }{4 \sqrt{3} - 3 \sqrt{2} } \\ \\ = > \frac{7 \sqrt{3}(4 \sqrt{3} - 3 \sqrt{2}) - 5 \sqrt{2}(4 \sqrt{3} - 3 \sqrt{2} ) }{ {(4 \sqrt{3)} }^{2} - {(3 \sqrt{2)} }^{2} } \\ \\ = > \frac{84 - 21 \sqrt{6} - 20 \sqrt{6} + 30 }{48 - 18} \\ \\ = > \frac{114 - 41 \sqrt{6} }{30}$

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$\large \pink{{Hope \: you \: got \: it}}$