Math, asked by mohitkaidan, 1 month ago

7+3√5/3+√5-7-3√5/3-√5 Rationalisation​

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Answered by Roefa
0

Answer:

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Answered by sandy1816
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 \frac{7 + 3 \sqrt{5} }{3 +  \sqrt{5} }  -  \frac{7 - 3 \sqrt{5} }{3 -  \sqrt{5} }  \\  \\  =  \frac{(7 + 3 \sqrt{5} )(3 -  \sqrt{5}) - (7 - 3 \sqrt{5} )(3 +  \sqrt{5} ) }{9 - 5}  \\  \\  =  \frac{21 - 7 \sqrt{5} + 9 \sqrt{5}   - 15 - 21 - 7 \sqrt{5} + 9 \sqrt{5}  + 15 }{4}  \\  \\  =  \frac{4 \sqrt{5} }{4}  \\  \\  =  \sqrt{5}

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