Question

7+3√5 / 3+√5 - 7-3√5 / 3-√5 simplify it

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } - \frac{7 - 3 \sqrt{5} }{3 - \sqrt{5} } \\ \\on \: rationalizing \: we \: get \\ \\ \frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } \times \frac{3 - \sqrt{5} }{3 - \sqrt{5} } - \frac{7 - 3 \sqrt{5} }{3 - \sqrt{5} } \times \frac{3 + \sqrt{5} }{3 + \sqrt{5} } \\ \\ using \: th \: identity \\ (a + b)(a - b) = {a}^{2} - {b}^{2} \\ \\ \frac{7 \times 3 - 7 \times \sqrt{5} + 3 \sqrt{5} \times 3 - 3 \sqrt{5} \times \sqrt{5} }{ {(3)}^{2} - ( { \sqrt{5} )}^{2} } \\ - \frac{7 \times 3 + 7 \times \sqrt{5} - 3 \sqrt{5} \times 3 - 3 \sqrt{5} \times \sqrt{5} }{ {(3)}^{2} - {( \sqrt{5}) }^{2} } \\ \\ = \frac{21 - 7 \sqrt{5} + 9 \sqrt{5} - 15}{9 - 5} - \frac{21 + 7 \sqrt{5} - 9 \sqrt{5} - 15}{9 - 5} \\ \\ = \frac{6 + 2 \sqrt{5} }{4} - \frac{6 - 2 \sqrt{5} }{4} \\ \\ = \frac{6 + 2 \sqrt{5} - 6 + 2 \sqrt{5} }{4} \\ \\ = \frac{4 \sqrt{5} }{4} \\ \\ = \sqrt{5}$

Hope this helps!!!!

@Mahak24

Thanks...
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Answer 2

Answer:√5

This is correct according to my teacher

So please give thanks to the one who had mentioned similar answer to me.