Math, asked by ankushsingh98, 11 months ago

7 + 3 √5÷7-3√5=a+b√5 then find the value of a and b​

Answers

Answered by Anonymous
6

Answer:

7+3√5/(3+√5) - 7-3√5/(3-√5) a + √5b

= (7+3√5)(3-√5) - (7-3√5)(3+√5)/(3+√5)(3-√5) = a + √5b

21-7√5+9√5-15-21-7√5+9√5+15/9-5 = a + √5b

4√5/4 = a + √5b

√5 = a + √5b

Comparing both left and right hand side a = 0 and b = 1

Thus a = 0 and b= 1

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