Question

7+√3/7-√3
$simplify$
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Answer 1

Answer:

i hope it's help you

Step-by-step explanation:

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\begin{gathered} \frac{(7 + \sqrt{3} )}{(7 - \sqrt{3}) } \\ \frac{(7 + \sqrt{3} )}{(7 - \sqrt{3}) } \times \frac{(7 + \sqrt{3}) }{(7 + \sqrt{3} )} \\ \frac{ {(7 + \sqrt{3}) }^{2} }{ {7}^{2} - { \sqrt{3} }^{2} } \\ \ \frac{49 + 3 + 14 \sqrt{3} }{4} \\ \frac{52 + 14 \sqrt{3} }{4} \\ 13 + \frac{7}{2} \sqrt{3} \end{gathered}

(7−

3

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(7+

3

)

(7−

3

)

(7+

3

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×

(7+

3

)

(7+

3

)

7

2

−

3

2

(7+

3

)

2

4

49+3+14

3

4

52+14

3

13+

2

7

3

Answer 2

Answer:

$\frac{26 + 7 \sqrt{3} }{23}$

Step-by-step explanation:

$\frac{7 + \sqrt{3} }{7 - \sqrt{3} } \\ = \frac{(7 + \sqrt{3})(7 + \sqrt{3}) }{(7 + \sqrt{3})(7 - \sqrt{3} ) } \\ = \frac{49 + 14 \sqrt{3} + 3 }{49 - 3} \\ = \frac{52 + 14 \sqrt{3} }{46} \\ = \frac{26 + 7 \sqrt{3} }{23}$