Question

[(7)^-3 ÷ (7)^-8]×7^-6​

Answer 1

Answer:

$7^{-3$

Step-by-step explanation:

(7)^-3 = 1/(7)^3

(7)^-8 = 1/(7)^8

= 1/7^3 / 1/7^8

= 1/7^3 x 7^8/1

= 7^8/7^3

a^m/a^n = a^(m-n)

= 7^(8-5)

= 7^3

7^3 x 7^-6 = 7^3 x 1/7^6

= 7^3/7^6

= 7^(3-6)

= 7 ^ -3

$= 7^{-3$

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Answer 2

Answer:

first let's calculate the ones in brackets

7^-3÷7^8=7^-3-(-8)=7^-3+8=7^5

now the result outside the bracket

7^5×7^-6=7^5+-6=7^5-6=7^-1=-7

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