Question

(7^-3+8^-2)^0 answer my question pls​

Answer 1

Solution: (7^−2+8^−2)^0=1

Answer 2

Answer:

$question) \: \: = \: \: ({7}^{ - 3} + {8}^{ - 2} {)}^{0} \\ = ( ( \frac{1}{7})^{3} + (\frac{1}{8})^{2}) ^{0} \\ = (\frac{1}{343} + \frac{1}{64} )^{0} \: \: \: formula \: \: \: \: a ^{0} = 1. \\ = 1 \: \: \: answer$