Question

7
3. A car accelerates uniformly from 18 km h-1 to
36 km h-1 in 5 s. Calculate (i) the acceleration and
(ii) the distance covered by the car in that time.​

Answer 1

Answer:

(i) 1 m/s^2 (ii)37.5m

Step-by-step explanation:

speed in km/h * 5/18 = speed in m/sec

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initial speed = 18km/h = 5m/s

final speed = 36km/h = 10m/s

acceleration = (final velocity - initial velocity)/time taken

=(10-5)/5=1m/s^2

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(final speed)^2 - (initial speed)^2 = 2*acceleration*distance

10^2 - 5^2 = 2*1*distance

2*distance = 75

distance = 37.5

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Hope it helps.