7.3
gm of organic compound contains 3.6 gmof carbon
1.4 gm Nitrogen 1.6 gm oxygen and rem
and remaning hydregen
find emperical formula of Compound
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Answer: C3NOH3
Explanation:
carbon+Nitrogen+oxygen+hydrogen=organic compound
3.6g + 1.4g + 1.6g + hydrogen = 7.3 g
calculate weight of hydrogen = 0.7 g
step 1 : convert in to moles of each element
Given mass/ molar mass= no.of moles
Moles of carbon =0.3
Moles of nitrogen=0.1
Moles of oxygen=0.1
Moles of hydrogen= 0.7
step 2: Divide the mole value obtained above by the smallest value
since 0.1 is smallest value divisible by its gives
3:1:1:3
step 3: write empirical formula by mention numbers after writing the symbols of element
C3NOH3
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