Question

7.3 grams of HCL is dissolved in 50 litres of aqua solution its pH 3 is​

Answer 1

Given:

Amount of HCl,w = 7.3 gm

Volume of solution,V = 50 L

To Find:

pH of the solution

Calculation:

- No of moles of HCl = 7.3 / 36.5 = 0.2

- Molarity, M = 0.2/50 = 0.004

- Since HCl is a strong acid, it dissociates completely into its ions.

Hence, concentration of hydronium ions, [H⁺] = 0.004

- Using formula of pH, we get:

pH = - log[H⁺]

⇒ pH = - log (0.004)

⇒ pH = - {log 2²  + log 10⁻³}

⇒ pH = - {2 log 2 - 3 log 10}

⇒ pH = - {2 × 0.3010 - 3 × 1}

⇒ pH = 2.398

- So the pH of HCl solution is 2.398